Substitute p=x^2

  • Thread starter nameVoid
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  • #1
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is there a way to solve this by hand
(1/2)x^4-x^2-1=0
 

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  • #2
Cyosis
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Yes substitute p=x^2.
 
  • #3
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(1/2)x^4-x^2-1=(1/2)p^2-p-1=0

quadratic in p

[1+||- (1+2)^(1/2) ] = 1+||-3^(1/2) = p = x^2

x=+||-[1+||-3^(1/2) ]^(1/2) =+||-[1+3^(1/2) ]^(1/2)
 
  • #4
Cyosis
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That's correct.
 

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