- #1

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## Homework Statement

$$\int_{0}^{2} r\sqrt{5-\sqrt{4-r^2}} dr$$

## Homework Equations

## The Attempt at a Solution

would i substitute ##u=4-r^2##?

After of which I would input in to the integral and get:

$$\int_{0}^{2} \sqrt{5-\sqrt{u}}du$$

What would I do here? Do I just work inside the radical(so 5r - 2/3u^3/2)? Or do I have to account that it's inside a radical when solving?