1. The problem statement, all variables and given/known data A mass is between 2 springs between 2 walls. The mass oscillates with amplitude d. The springs are at equilibrium when the mass is in the center. At the moment the mass is in the center a spring is removed. What is the resulting x(t) and the new amplitude? Note the k's are equal. Edit: I forgot to add that at t=0 x(t)=d/2 when there is one spring. 2. Relevant equations 3. The attempt at a solution So I solved for x(t) for both before and after removing the spring. Before: x(t) = Asin(2wt) + Bcos(2wt) after: x(t) = Asin(wt) + Bsin(wt) I'm just assuming the new amplitude is twice what is was since when the spring is removed it has the energy of 2 springs, but now the resistance of one. Is there a way to show this using the x(t)'s I found? I feel like they should relate to the problem more.