Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

  • Thread starter rick906
  • Start date
  • #26
The derivative of the Riemann-Zeta function has a log n term and it appears when you Taylor expand the fn as he suggested doing. The only thing is that the log n term appears in the numerator, I wonder how you watch it to the original series? Well the derivative of the Riemann-Zeta function at 2 is known exactly if you can end up matching that series with the original.
 
  • #27
1,838
7
Yes, I was wrong. The factor 4+ln(n) has to be in the numerator for this to work. See also http://mathworld.wolfram.com/Glaisher-KinkelinConstant.html" [Broken]
 
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