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Can I claim that in order to find the sum of the series:

[tex]\sum_{n = 0} ^{\infty} 2^{- n}[/tex]

[tex]\sum_{n = 0} ^{\infty} 2^{- n} = \sum_{n = 0} ^{\infty} x^n = \frac{1}{1-x} [/tex] ???

Sincerely Yours

Fred

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# Homework Help: Sum of a geometric series

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