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A skier on a slope inclined at 4.7 degrees to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7m/s. The coefficient of kinetic friction between skies and snow is 0.11. Determine how far the skier will slide before coming to rest.

So far i had done the following, but i am unsure if this is the right way to go about this and also what to do next to find the answer.

in the perpendicular

0 = mgcos4.7 [D] + Fn

Fn = mgcos4.7

Fn = mgcos4.7

Ff = 0.11(mgcos4.7)

parallel

Fnet = Ff + Fgperp + fapp

0 = mgsin4.7 - 0.11(mgcos4.7) - Fapp

Fapp = 0.27(m)Ff = 0.11(mgcos4.7)

parallel

Fnet = Ff + Fgperp + fapp

0 = mgsin4.7 - 0.11(mgcos4.7) - Fapp

Fapp = 0.27(m)