hi, i need a little help calculating the infinite series sorry if it seems confusing, but i dont know how to put in the sigma or intergral symbols i did my best to make it clear:(adsbygoogle = window.adsbygoogle || []).push({});

i am sopposed to express (integral from 0 to 1) of 2dx/[(3x^4)+16] as a sum of an infinite series heres what i did:

the (integral from 0 to 1) of 2dx/[(3x^4) + 16]

i found that the series of 2dx/[(3x^4)+16] = 1/8* (sigma from n=0 to infinity) of (-1)^n *(3x^4/16)^n

i then pulled out the constants and got

1/8 * (sigma from n=0 to infinity) (-1)^n * (3/16)^n (integral from 0 to 1) (x^4n)

after evaluating the integral i got for my infinit series

1/8 (sigma from n=0 to infinity) (-1)^n (3/16)^n [1^(4n-1)/4n-1]

i just wanted to know if this seemed like it was the right way.

thanks

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# Homework Help: Sum of an infinite series

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