- #1

- 13

- 0

check my algoriathm, let y=2^1000 then logy = 1000log2 = 301 and y=10^logy=10^301

since (1,0) r da only digits of 10^n 4all n=1,2,3,4,..... The sum of digits equals 1 , but it is not the answer ...Why?

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- Thread starter Krypton
- Start date

- #1

- 13

- 0

check my algoriathm, let y=2^1000 then logy = 1000log2 = 301 and y=10^logy=10^301

since (1,0) r da only digits of 10^n 4all n=1,2,3,4,..... The sum of digits equals 1 , but it is not the answer ...Why?

- #2

- 1,074

- 1

- #3

- 1,056

- 0

However the problem can be worked out by looking at the series, 2, 4, 8, 16=7, 32=5, etc.

- #4

- 13

- 0

Hay i am not using a computer to calculate it that way. I need some techiques could u plzzzzz....Z

- #5

uart

Science Advisor

- 2,776

- 9

If its the single digit reduced sum that you want then just work modulo 9 to get the answer (which is

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