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Sum of real numbers

  1. Apr 9, 2010 #1
    1. The problem statement, all variables and given/known data
    if the real numbers x,y,z,w satisfy (x2/(n2-1))+(y2/(n2-32))+(z2/(n2-52))+(w2/(n2-72)) for n=2,4,6,8 then prove
    x2+y2+z2+w2=36




    2. Relevant equations



    3. The attempt at a solution
    unable to think of anything???:confused:
     
  2. jcsd
  3. Apr 9, 2010 #2

    radou

    User Avatar
    Homework Helper

    Unless I'm missing something, the problem you posted isn't consistent - what do your numbers x, y, z, w satisfy?
     
  4. Apr 9, 2010 #3

    sorry the exact equation is as follows
    [(x2/(n2-1))+(y2/(n2-32))+(z2/(n2-52))+(w2/(n2-72))]=1
     
  5. Apr 10, 2010 #4
    plz help:confused::confused:
     
  6. Apr 10, 2010 #5

    Mark44

    Staff: Mentor

    Edit: Add "= 1" to make an equation below.
    You're unable to think of anything? The most obvious starting point is substituting n = 2, n = 4, n = 6, and n = 8, and seeing what you get.
     
  7. Apr 10, 2010 #6

    D H

    User Avatar
    Staff Emeritus
    Science Advisor

    That will give you four different equations in four unknowns -- in other words, exactly what is needed to solve the problem.
     
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