Calculate the Sum of Series: \sum_{n=1}^{\infty}n(n+1)x^n for Homework

In summary, the sum of the series \sum_{n=1}^{\infty}n(n+1)x^n is given by x\frac{x^2}{1-x}, which can be found by taking the second derivative of the function x^2/(1-x).
  • #1
azatkgz
186
0

Homework Statement


Find the sum of the following series

[tex]\sum_{n=1}^{\infty}n(n+1)x^n[/tex]


The Attempt at a Solution




[tex]x\sum_{n=1}^{\infty}n(n+1)x^{n-1}[/tex]

[tex]x\int_{0}^{x}(\int_{0}^{x}f(t)dt)dt=x(x^2+x^3+x^4+x^5+\cdots)=x\frac{x^2}{1-x}[/tex]


[tex]x\frac{d^2}{dx^2}\frac{x^2}{1-x}=\frac{2x}{1-x}[/tex]
 
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  • #2
I am not really sure of how to do this but looking at your last line, I think you messed up taking the second derivative of x^2/(1-x) since you need to use the quotient rule, the (1-x) should be squared on each derivative
 

1. What is the formula for calculating the sum of series?

The formula for calculating the sum of series is Sum = a / (1-r), where a is the first term and r is the common ratio.

2. How do I identify the first term and common ratio?

In the given series, the first term is a = 1 and the common ratio is r = (n+1)x.

3. Can this series be summed using a closed-form formula?

Yes, this series can be summed using the closed-form formula Sum = a / (1-r).

4. Is there a limit to the number of terms that can be summed in this series?

No, there is no limit to the number of terms that can be summed in this series, as it is an infinite series with n starting at 1 and continuing to infinity.

5. How do I know if the series converges or diverges?

In order to determine if the series converges or diverges, you can use the Ratio Test or the Root Test. If the limit of the ratio or root is less than 1, then the series converges. If the limit is greater than 1, then the series diverges. If the limit is equal to 1, then the test is inconclusive and further analysis is needed.

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