# Sum of the Series

1. Aug 10, 2008

### LeonJHardman

1. The problem statement, all variables and given/known data
Find the sum of the series $$\sum$$$$^{\infty}_{0}$$$$\frac{(-9)^{n}}{(2n+1)!}$$

2. Relevant equations
Alternating series Estimation Theroem

3. The attempt at a solution
I think it satisfies the conditions necessary for an alternating series to converge. The limit as n approaches infinity of b$$_{n}$$=0, and b$$_{n}$$>b$$_{n+1}$$. So listing out the terms I get 1-(9/6)+(81/120)-(720/5040)+... But at this point I'm not sure how far to expand the series, because the problem just says find the sum of the series, which makes me think that there would be an exact answer, but I can't think of another way to find a sum. It's not a geometric sequence, and I don't think I could estimate it with integration either.

2. Aug 10, 2008

### Chrisas

Not sure how you are supposed to find the answer. If you replace the -9 with (-1)^n * (9)^n it looks close to the series expansion for sine. But you want n^2 +1 in the numerator power. Change the 9 to 3^2 gives you (3)^2n. Multiply outside the sum by 1/3 and inside by 3 gives you (3)^(2n+1). So you get (1/3) * sin(3).

3. Aug 10, 2008

### dynamicsolo

Does this

$$\sum^{\infty}_{n=0} \frac{(-1)^{n} \cdot x^{2n+1} }{(2n+1)!}$$

remind you of, oh, say, any particular Maclaurin series you may have seen before...? (It converges for any real x. Many problems in infinite series are set where you're expected to recognize what function the series represents in order to evaluate it...)

Now, what you have is not quite the same, but that can be easily fixed. Write out the first few terms of this series and of your series. In comparing the two, you should notice what must be done to express your series in terms of a multiple of a familiar function...

What you described is pretty much what the student is asked to notice. But, here at PF, you really shouldn't just hand out the answer as well...

Last edited: Aug 11, 2008