- #1

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([tex]\sum[/tex][tex]^{n}_{i=1}[/tex] x[tex]_{i}[/tex])[tex]^{2}[/tex]

- Thread starter LordCalculus
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- #1

- 12

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([tex]\sum[/tex][tex]^{n}_{i=1}[/tex] x[tex]_{i}[/tex])[tex]^{2}[/tex]

- #2

- 754

- 1

I assume you mean:

[tex]\left(\sum_{i=1}^n x^i \right)^2[/tex]

[tex]\left(\sum_{i=1}^n x^i \right)^2[/tex]

- #3

- 754

- 1

It already *is* in summation notation!

(or, are you trying to come up with a summation equal to this, in which the result is not squared?)

in the form of:

[tex]\sum_{i=a}^b f(x,i)[/tex]

(or, are you trying to come up with a summation equal to this, in which the result is not squared?)

in the form of:

[tex]\sum_{i=a}^b f(x,i)[/tex]

Last edited:

- #4

- 754

- 1

For n=2, you get [itex] (x^1 + x^2)^2 = x^2 + 2x^3 + x^4[/tex]

For n=3, you get [itex]x^2 + 2x^3 + 3x^4 + 2x^5 + x^6[/tex]

For n=4, you get [itex]x^2 + 2x^3 + 3x^4 + 4x^5 + 3x^6 + 2x^7 + x^8[/tex]

Notice any pattern?

Are you're looking for the summation notation for this series, given n?

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