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Summer Assignment Problem Help

  1. Sep 3, 2011 #1
    1. The problem statement, all variables and given/known data
    Density + Uncertainty of block?
    The mass of a rectangular block is measured to be 2.2 kg with an uncertainty of 0.2 kg. The sides are measured to be 60 +/- 3mm, 50 +/- 1 mm, and 40 +/- 2mm. Find the density of the block in kilograms per cubic meter, giving the uncertainty in the result.


    2. Relevant equations
    D=m/V


    3. The attempt at a solution
    Mass = 2.2 +/- 0.2kg
    Volume = 60mm x 50mm x 40mm = 120000mm3

    then... 1/50 = .02, 3/60 = .05, 2/40 = .05 ---> sum = .12

    120000mm3 x .12 = 14400

    therefore V = 120000 +/- 14400mm^3 (Please help me convert this to cubic meters)

    D=m/V
    =2.2/120000 (really not supposed to use this until i get proper conversion)
    = ???

    Thanks
     
  2. jcsd
  3. Sep 3, 2011 #2
    Hi Wa1337,
    Finding errors of things takes a little practice, as I'm sure you'll find out soon enough! As you correctly point out, Density = mass / volume. If you're multiplying or dividing, you need to use relative errors (e.g. percentages), not the absolute errors you have provided. Finding the relative error is easy though; all you need to do is take the absolute error ([itex]dx[/itex]), and divide it by the measurement ([itex]x[/itex]). So, for mass, the relative error is [itex]\frac{dx}{x} =\frac{0.2}{2.2} = 0.091[/itex]. I'll let you work out the rel. errors for the dimensions.

    You mentioned that you need help converting mm3 to m3, and I agree, it's a bit tricky. You will find it much easier if you started your volume calculation with metres to start with since converting mm to m is much easier.

    So, if you make the Density = Mass / Vol calculation, that'll obviously give you the density. To find the error on this density, you need to add your relative errors 'in quadrature'. All this means is that you square all of your relative errors, add them together, and take the square root (i.e. [itex]\sqrt{(\frac{dx}{x})^2 +(\frac{dy}{y})^2 + (\frac{dz}{z})^2 +... }[/itex]) This will give you the relative error of your density. If you need the absolute error of the density, you must multiply the relative error by the value you got for the density.
     
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