Summing 4-Digit Numbers with 1,2,3,4

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The discussion focuses on calculating the sum of all 4-digit numbers formed by the digits 1, 2, 3, and 4 with repetition allowed. Participants determine that there are 256 possible combinations and explore methods to sum them without listing each number. They realize that by analyzing the vertical patterns of the digits, they can simplify the addition process. The final insight is that the total sum can be calculated by recognizing that each digit contributes equally across all positions, leading to a straightforward calculation that involves dividing by two to avoid double counting. The solution is confirmed to be simpler than initially thought.
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Find sum!

Homework Statement



Find sum of all 4-digit numbers formed by digits 1,2,3,4 with repetition.


The Attempt at a Solution


i did come figure out that there are 44 = 256 numbers possible but how do i sum them up without listing each individually?
 
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Can you arrange them in increasing order? Which one is the smallest, the next and so on?
 


ok, that would give me something like this

1111
1112
1113
1114
1121
1122
.... and so on but how will that help? :confused:
 


why don't you look at the vertical pattern of the numbers you're writing out...
 


ow foolish me!
so i get it there's repetition of 1+2+3+4 in units and in tens 1+1+1+1+2+2+2+2... so on and adding them a bit cleverly(though it does consume some time!) as you guys suggested and I got the answer.
so thanks for helping me out! :approve:
 


I would make an other column beside this one, but the numbers would be in decreasing order...

ehild
 


oh .. i see.. this is even quite easier than i suspected!

Thanks again! :smile:
 


... so what did you come up with?
 


ehild said:
I would make an other column beside this one, but the numbers would be in decreasing order...

ehild

and I would add up the two numbers in one row...

ehild
 
  • #10


adding up as ehild said i get same terms ie= 5555 256 times!
so what would happen is we get twice the sum actually needed and dividing it by 2 ... easy answer!
 
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