- #1

- 394

- 2

The book has that expression equal to

[tex]\sum[/tex] (4/11)^n - [tex]\sum[/tex] (-7/11)^n

I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?

- Thread starter kuahji
- Start date

- #1

- 394

- 2

The book has that expression equal to

[tex]\sum[/tex] (4/11)^n - [tex]\sum[/tex] (-7/11)^n

I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?

- #2

nicksauce

Science Advisor

Homework Helper

- 1,272

- 5

Fact:

[tex](x^y)^z = x^{yz}[/tex].

Does that help you out?

[tex](x^y)^z = x^{yz}[/tex].

Does that help you out?

- #3

- 394

- 2

Crude, nm. 2am & math doesn't mix sometimes. ^_^

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