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[tex]\sum[/tex] (2^(2n)-(-7)^n)/(11^n)
The book has that expression equal to
[tex]\sum[/tex] (4/11)^n - [tex]\sum[/tex] (-7/11)^n
I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?
The book has that expression equal to
[tex]\sum[/tex] (4/11)^n - [tex]\sum[/tex] (-7/11)^n
I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?