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I'm working on a lengthy problem, and one part asks to find the height of the Sun above the horizon as a function of time. I came up to this solution:

[tex]\tan (\theta+h) = \frac{\cos (\omega t)}{\tan \phi}[/tex]

where [tex]\theta[/tex] is Sun's height below (or above) the celestial equator (i.e. -23.4 deg in winter solstice), while [tex]\phi[/tex] is the latitude of observation place. [tex]\omega t[/tex] is the phase of Sun's revolution if noon is the point of reference. I've checked many times that this formula is correct, however I have problems and I suspect that this might not be correct after all, because I have a factor of about 2 missing. Can you verify that this is a correct result?

I could post my solution to obtain this formula, if necessary.

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# Homework Help: Sun's height above the horizon

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