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Supersonic airplane emits a sound when right over a listener
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[QUOTE="krvolok, post: 4546997, member: 491873"] Hello, I'm having a bit of a problem with the following problem: A supersonic airplane flying at the velocity v is flying horizontally to the ground with altitude h. At the exact moment when the plane is vertically above a listener on the ground, it emits a sound. It takes Δt seconds for the sound to reach the listener. What is the velocity of the airplane if the speed of sound is c. The solution given is v=c/√(1-(c*Δt/h)^2). It's short so I'm not using latex :) Anyway, my reasoning is that the sound will go straight down with speed c, since it can't go any faster. But then, this height h=c*Δt, and if you try putting that in the answer bad things happen. Could someone explain why h =/= c*Δt and how to get that weird proportion. At least give me some hints :) Thank you very much! [/QUOTE]
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Supersonic airplane emits a sound when right over a listener
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