# Surface Area 1

The part of the plane 3x+2y+z=6 that lies in the first octant.

$$A(s)=\int_0^2\int_0^3\sqrt{14}dydy$$

Are my limits not correct? B/c my answer is just off by a little.

me: 6\sqr(t14), answer: 3\sqrt(14)

## Answers and Replies

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