Find the area of the surface obtained by rotating the curve y=2e^(2y) from y=0 to y=4 about the y-axis. Any help on this would be greatly appreciated. This has my whole hall stumped. We know that you have to use the equation 2pi*int(g(y)sqrt(1+(derivative of function)^2), but cannot figure out how to integrate this correctly. What I have gotten so far: y=2e^(2y) [when u=2y, du/2=dx] y=e^u New bounds: 1 to e^4 2pi*int(e^u*sqrt(1+(e^u)^2) How do you go from there? Any help would be greatly appreciated.