1. The problem statement, all variables and given/known data f(x) = 1/x Interval [1, ∞) about the x-axis Set-up the integral for the surface area of the solid Then use the substitution u = x2 and integrate using the formula: ∫ sqrt(u2 + a2) / u2 du = ln(u + sqrt(u2 + a2) - sqrt(u2 + a2) / u + C a is a constant 2. Relevant equations S = 2pi * ∫ (f(x) * sqrt(1 + [f`(x)]2) dx from a to b 3. The attempt at a solution First, I found the derivative of (1/x) which is -1/x2 I then plugged f(x) and f`(x) into the surface area equation I squared f`(x) to get (1/x4) My equation is 2pi ∫ (1/x) * sqrt(1 + (1/x4) from 1 to infinity of course, which I will change to the limit as b approaches infinity because it is an improper integral. I simplified the fractions under the radical to get sqrt((x4 + 1) / x4) I took the square root of the denominator to get x2 Lastly, I multiplied (1/x) by sqrt(x4 + 1) / x2 to get sqrt(x4 + 1) / x3 If u = x2 then this is not in the correct form to use the formula that was given to me. How can I get the denominator to equal x4? I will figure out the rest of the problem from there. Here is my written attempt: Thanks!