Find the surface area when this curve is revolved around the x ax(adsbygoogle = window.adsbygoogle || []).push({});

x = 1/3(y^2 + 2)^3/2 [1,2]

I set it up both ways and i get two really complicated integrals.

[tex]2 \pi/3 \int_1^2 \sqrt{\frac{y^2+y^4}{(y^2+2)^{2/3}}} dy [/tex]

Yeah I cant figure out how to do this integral, and Im thinking there must be an easier way. The other way, integrating with x, seemed even more complicated If anyone can give me some hints, it'll be appreciated. Thanks.

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# Homework Help: Surface Area

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