- #1

- 13

- 0

surface area = ( y) ( 1+ f ' (x)^(2) )^(1/2)

equal

surface area = (x ) (1+ f ' (x)^(2) )^(1/2)

the simplest explanation please.

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- Thread starter calculushelp
- Start date

- #1

- 13

- 0

surface area = ( y) ( 1+ f ' (x)^(2) )^(1/2)

equal

surface area = (x ) (1+ f ' (x)^(2) )^(1/2)

the simplest explanation please.

- #2

Defennder

Homework Helper

- 2,591

- 5

For a surface area of a function in 3D, for which the surface z(x,y) is given, the surface area of the portion that projects down onto a region R is given by [tex]\int \int_R \sqrt{\left(\frac{\partial z}{\partial x} \right)^2 + \left(\frac{\partial z}{\partial y}\right)^2 + 1} \ \ dA [/tex]

- #3

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

surface area = ( y) ( 1+ f ' (x)^(2) )^(1/2)

equal

surface area = (x ) (1+ f ' (x)^(2) )^(1/2)

the simplest explanation please.

There can be no explanation- what you have written makes no sense at all! Are there supposed to be integrals in there?

Are you talking about the area of surfaces of rotation?

- #4

- 13

- 0

yes! in rotation! sorry i didnt know how to put an integral sign.

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