a square of side 2a is uniformly charged with a surface density [tex]\rho[/tex](adsbygoogle = window.adsbygoogle || []).push({});

find the potential at a point distance a directly above the midpoint of one of the sides, express your answer as a numerical multiple of [tex]k_e \rho a[/tex].

wow ok soo... i got this going for me

[tex]

k \rho \int^a_{-a} \int^a_{-a} \frac{1}{\sqrt{(x-x')^2 + (y-y')^2 + z^2}}dy' dx' [/tex] where (x,y,z) is the point simple enough..how do i evaulate this...i know it goes all natural log on me...but damn what do i do then!? suggestions anyone?

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# Surface charge

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