1. The problem statement, all variables and given/known data Evaluate the double integral of yz dS. S is the surface with parametric equations x=(u^2), y=usinv, z=ucosv, 0<u<1, 0<v<(pi/2) (all the "less than" signs signify "less than or equal to" here) 2. Relevant equations double integral of dot product of (F) and normal vector over the domain 3. The attempt at a solution When I solved for the normal vector, I crossed r_u X r_v and got 5u^4. Then I solved the double integral of (u^4)sinvcosv(5u^4) dudv. u is from 0-->1 and v is from 0-->pi/2 My final answer came out to be pi/12, but it's wrong. Can anyone help?