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## Homework Statement

g(x,y,z) = z

^{2}; Ʃ is the part of the cone z = [itex]\sqrt{x

^{2}+y

^{2}}[/itex] between the planes z = 1 and z = 3.

## Homework Equations

Conversion to polar coordinates

∫∫

_{Ʃ}g(x,y,z)dS = ∫∫

_{R}g(x,y,f(x,y)) [itex]\sqrt{f

_{x}

^{2}+ f

_{y}

^{2}+1}[/itex]

## The Attempt at a Solution

If we're talking in terms of r and θ, r goes from 1 to 3 and θ goes from 0 to 2π. I converted to polar coordinates from cartesian and I got 8*π*√2 *z

^{2}. If you were converting to polar/cylindrical coordinates, z

^{2}wouldn't change, correct?

Sorry, for some reason the square root LaTeX command didn't want to work...