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Surface integral question

  1. Dec 8, 2012 #1
    Look in the paint doc. I was wondering why they said z = rcos(θ) and not z = rsin(θ) and x = rcos(θ)

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  2. jcsd
  3. Dec 8, 2012 #2


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    The set-up is symmetric between x and z, so does it matter which is equated with the cos and which with the sin?
  4. Dec 8, 2012 #3
    Well when i used sine I came out with a different answer but ill try again.
  5. Dec 9, 2012 #4
    You are right the answers are the same. thanks.
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