(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

So trying to find the Integral of A.n dS where A is (y,2x,-z) and S is the surface of the plane 2x+y = 6 in the first octant cut off by the plane z=4

2. Relevant equations

3. The attempt at a solution

So i always solve these by projection...but im a bit confused this time..

normally the surface is in the form z=f(x,y) so i do z-f(x,y) and take grad to find the normal..

so is the normal vector here just (2,1)? ie. grad 2x-y-6 = 0?

In which case is the integral just the double integral of (y,2x,-4).(2,1,0) dA?

Im a bit confused..Any help would be great!

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# Homework Help: Surface Integral

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