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Homework Statement
So trying to find the Integral of A.n dS where A is (y,2x,-z) and S is the surface of the plane 2x+y = 6 in the first octant cut off by the plane z=4
Homework Equations
The Attempt at a Solution
So i always solve these by projection...but I am a bit confused this time..
normally the surface is in the form z=f(x,y) so i do z-f(x,y) and take grad to find the normal..
so is the normal vector here just (2,1)? ie. grad 2x-y-6 = 0?
In which case is the integral just the double integral of (y,2x,-4).(2,1,0) dA?
Im a bit confused..Any help would be great!