Surface Integrals

  • #1
Find the surface area of the the portions of the cylinder y^2 + z^2=a^2 bounded by x^2 + y^2 = a^2


not really sure how to go about this. tried to set up a double integral and use polar coordinates but dont know what boundaries to use etc.
 

Answers and Replies

  • #2
tiny-tim
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Welcome to PF!

Hi s_engineering! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
  • #3
this is what i've tried:

fy = 2y; fz=2z

A(S)=int int sqrt{1+4y^2 +4z^2}dA

then I switched to polar coordinates i tired to integrate from theta=0 to pi/2 and r= 0 to a
but didn't get anywhere with this.
 

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