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> - Current in wire 1 vs. current in wire 2.

> - Electric field in wire 1 vs. electric field in wire 2.

The solutions say that current 1 = current 2 and that electric field 1 = electric field 2.

How does the length of the wire affect these two quantities? According to Kirchhoff's Law: $$\Delta V=RI$$.

$$R=\frac{L\rho}{A}\implies$$ Resistance of wire 2 is twice the resistance of wire 1. Therefore, the current in wire 2 will be twice as small as wire 1.

Finally, we know that $$J=\sigma E$$ The resistivity is the same because the material is the same. So, the electric field will be twice as small for wire 2.

The solutions manual seems wrong. Am I right or is there a problem in my reasoning?