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## Homework Statement

Evaluate integral A.n dS for A=(y,2x,-z) and S is the surface of the plane 2x+y=6 in the first octant of the plane cut off by z=4

## Homework Equations

Integral A.n dS

## The Attempt at a Solution

The normal to the plane is (2,1,0) so the unit normal vector is 1/sqrt3 (2,1,0).

A.n= 1/sqrt3(2y,2x,0)

So this is where I get stuck. I think it goes as follows....

ds= dxdy

=> double integral 2/sqrt3 y + 2/sqrt3 x dxdy

And I'm not sure how to find the limits....