Evaluate integral A.n dS for A=(y,2x,-z) and S is the surface of the plane 2x+y=6 in the first octant of the plane cut off by z=4
Integral A.n dS
The Attempt at a Solution
The normal to the plane is (2,1,0) so the unit normal vector is 1/sqrt3 (2,1,0).
So this is where I get stuck. I think it goes as follows....
=> double integral 2/sqrt3 y + 2/sqrt3 x dxdy
And I'm not sure how to find the limits....