1. The problem statement, all variables and given/known data A cylindrical container of water with a radius of 6.0 cm is placed on a phonograph turntable so that its outer edge just touches the outer edge of the turntable. The radius of the turntable is 14.5 cm, and the turntable rotates at 33 and a 1/3 revolutions per minute. How much is the water depressed in the centre compared to the outer edge of its container? 2. Relevant equations gz − 1/2 ω2 (x2 + y2 ) = constant 3. The attempt at a solution I know that x2+y2 is equal to the radius squared. I think from my notes it's equal to the radius squared of the water in the container. So plugging this in, and omega I calculated to be 3.49 rad/s, I get a height of 0.0022 m. I'm not sure where to go from here though.