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How Does the Cassie-Baxter Model Explain the Lotus Effect?
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[QUOTE="Klaus von Faust, post: 6058539, member: 648999"] [B]1.[/B]The lotus effect refers to self-cleaning properties that are a result of [URL='https://en.wikipedia.org/wiki/Ultrahydrophobicity']ultrahydrophobicity[/URL] as exhibited by the leaves of "lotus flower". Dirt particles are picked up by water droplets due to the micro- and nanoscopic architecture on the surface, which minimizes the droplet's adhesion to that surface. If the apparent contact area of a droplet with such a surface is A, and the real contact area because of the microscopic whiskers is xA with x = 0.003, what is the contact angle? Assume that without “whiskers”, the contact angle would be α0 = 110 ◦ .[B]2. F = σa U = Sσ[/B] [IMG]https://wikimedia.org/api/rest_v1/media/math/render/svg/e7d4f0384ad54c7229f9e136509bb9076092bbe2[/IMG] [IMG]https://wikimedia.org/api/rest_v1/media/math/render/svg/7f8b53f214de5ac4cd0f8a092ae11529ba53b68c[/IMG] [IMG]https://wikimedia.org/api/rest_v1/media/math/render/svg/5ecad9324b653bc99f252908942078cb6675b421[/IMG] [B]3. [/B]I tried to use the fact that the volume is being constant, and I assumed that the drop has the shape of a spherical cap, so I expressed it's volume in terms of contact angle. A/xA=pi*R^2/pi*r^2 V=const V=pi/3*R^3*(2+cos(a))(1-cos(a))^2=pi/3*r^3*(2+cos(b))(1-cos(b))^2 [B][B]But the equation I have obtained which is not solvable. Can you help me and show another approach?[/B][/B] [/QUOTE]
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How Does the Cassie-Baxter Model Explain the Lotus Effect?
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