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Suspension of a car

  1. Sep 8, 2016 #1
    1. The problem statement, all variables and given/known data
    A guy is 60 kg and he gets in a car which is 500 kg. the center gravity of the car is 0.3 cm lower, find the spring constant of the suspension
    2. Relevant equations
    F = -kx
    F = mg
    3. The attempt at a solution

    I got the answer but it s very low valve, the springs of the car should be high, don't they?
    here 's my equation
    There are 2 forces acting on the car, Weight and Restoring Force of springs then
    mg = -kx
    ( 560 kg )( -9.8 m/s2 ) = - (k) ( 0.3x10-2 m )
     
  2. jcsd
  3. Sep 8, 2016 #2

    BvU

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    How low ?
     
  4. Sep 8, 2016 #3
    sorry,my mistake
    I've re calculated it, I got a pretty high valve instead, does it this valve is possible?
    k = ( 560 kg )( 9.8 m/s2 )( 102 ) / 0.3
    k = 1829333.333 N/m
     
  5. Sep 8, 2016 #4

    BvU

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    Not that low, then. But wrong.
    There is one small thing: the 0.3 cm is caused by how many kilograms ?
     
  6. Sep 8, 2016 #5
    60 kg of a man, oops
    k = ( 60 kg )( 9.8 m/s2 )( 102 ) / 0.3
    k = 196,000 N/m
     
  7. Sep 8, 2016 #6

    BvU

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    Way to go ! Well done.
     
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