1. The problem statement, all variables and given/known data A golfer is about to hit a golf ball from a tee to a hole on the green. The tee and the green are at the same level. The golfer hits the ball, projecting it at a speed of 35 m/s 28° to the horizontal. Air resistance is negligible. Calculate: a) the horizontal distance travelled by the ball before first landing on the green (2 marks) b) the maximum height reached by the ball above the level of the tee (2 marks) 2. Relevant equations SUVAT 3. The attempt at a solution a) On the horizontal plane: s = ? u = 35cos28 = 30.9 m/s v = ? a = 0 t = ? Okay, let's see if we can find v. With the horizontal component of the velocity remaining constant, we'd need to work out the vertical component and resolve. But I'd need the time to work out the final vertical component with v = u + at, which is useless, because I'd be able to use d = st if I had the time. I'm not seeing an obvious way to find it. EDIT: Hold up - I'm just looking at the horizontal component here, and that's going to remain constant, so v = u = 30.9 m/s. But where would I go from here? Could I just double the value for time I found in part b), since the maximum height would be at the half point of the trajectory? (Right?) 1.67 x 2 = 3.34s 3.34 x 30.9 = 103.2m. Anyone? b) On the vertical plane: s = ? u = 35sin28 = 16.4 m/s v = 0 a = -9.8 t = (0 - 16.4) / -9.8 = 1.67s s = (16.4 x 1.67) + (0.5 x -9.8 x 1.672) = 13.7m. Can someone confirm?