1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Symbolic Acceleration Problem

  1. Apr 6, 2009 #1
    1. The problem statement, all variables and given/known data
    When force F(force is at an angle Theda) is not too large, box m1(smaller top box) moves with box m2(bigger bottom box) without sliding. Find the magnitude of the acceleration of the two blocks.(see attachment)



    2. Relevant equations
    F=ma


    3. The attempt at a solution
    This is from a test that I took and I just wanted to make sure to see if I really did this wrong. The test is all symbolic, by the way.
    Fcos(x)-F(friction kinetic)=(m1+m2)a (this is the system equation for the right-left direction)
    F(normal)-(m1+m2)g=0 (this is the system equation for the up-down direction)
    F(friction kinetic)=F(normal)*(coefficient of kinetic friction)

    In order to figure out the acceleration, I got acceleration by itself and plugged in the 3rd equation into F(friction) in the first equation.
    Fcos(x)-F(normal)*(coeff.)=(m1+m2)a

    Then I used the second equation and replace the force normal:

    Fcos(x)-(m1+m2)g*(coeff)=(m1+m2)a

    Then after some math, I got this:

    Fcos(x)=(m1+m2)a+(m1+m2)g(coeff)
    (Fcos(x)/(m1+m2))=a+g(coeff)
    (Fcos(x)/(m1+m2))-g(coeff)=a

    So can anyone double check this to see if this works out or if the professor is right and this is totally wrong? Figure1.jpg
     
  2. jcsd
  3. Apr 6, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    This equation is not correct. If should be ...

    Fn = (m1 + m2)*g + F*sinθ

    Which means that

    Ffr = μk*((m1 + m2)*g + F*sinθ)

    etc.
     
  4. Apr 6, 2009 #3
    oh wow that explains a lot thanks!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Symbolic Acceleration Problem
  1. Acceleration Problem (Replies: 1)

  2. Acceleration problem (Replies: 4)

Loading...