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Symmetry in graphs

  1. Apr 13, 2010 #1
    For a graph of any function, one of following conditions is said to exist so as for it to be symmetric:
    a graph is symmetric about y-axis if along with a point (x,y) a point (-x, y) exists.
    a graph is symmetric about x-axis if along with a point (x,y) a point (x, -y) exists.
    a graph is symmetric about origin if along with a point (x,y) a point (-x, -y) exists.
    isn't it possible that one of the above condition is satisfied but still the graph is not symmetric. what i want to say is that can't it be possible for a curve to have such shape that it does not look symmetric but still passes through the two points highlighted by one of the conditions mentioned above?
     
  2. jcsd
  3. Apr 13, 2010 #2

    tiny-tim

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    Welcome to PF!

    Hi Danish_Khatri! Welcome to PF! :wink:
    I think it means for every (x,y) on the curve … :smile:
     
  4. Apr 13, 2010 #3
    Thanks for your help dear.... :-)
     
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