Find the point in respect to these ellipses are symmetrical
x2 + 3y2 - 2x -2 = 0
x2 + 3y2 +6x + 12y +18 = 0
x = 2a - x'
y = 2b - y'
The Attempt at a Solution
I have applied the equations of symmetry to the first equation then I've equaled the result to the second ellipse
4a2 + 12b2 - 4ax - 12bx - 4a -4x -20 -12y = 0
I don't know how to solve this for a and b or if I have mistaken something...