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Solve the following :
A) \(\displaystyle x^2-y\sqrt xy=126\)
\(\displaystyle y^2-x\sqrt xy=-63\)
B) \(\displaystyle \frac{x} {y}+\frac{y}{z}+\frac{z}{x}=\frac{y}{x}+\frac{z}{y}+\frac{x}{z}=x+y+z=3\)
A) \(\displaystyle x^2-y\sqrt xy=126\)
\(\displaystyle y^2-x\sqrt xy=-63\)
B) \(\displaystyle \frac{x} {y}+\frac{y}{z}+\frac{z}{x}=\frac{y}{x}+\frac{z}{y}+\frac{x}{z}=x+y+z=3\)