- #1

Punchlinegirl

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[tex]x_1[/tex]= 23.0t

[tex]x_2= -28.0 +43.0t-8.0t^2[/tex]

I solved the first equation for t, and then plugged it into the second one to get [tex]x_2= -28.0 + 43.0( \frac {x_1}{23}) -8.0(\frac {x_1}{23})^2[/tex]

I tried to use the quadratic formula but got a negative number... can someone tell me what I'm doing wrong? Thanks in advance.