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T and mg in a pendulum system

  1. Sep 26, 2007 #1
    I'm having trouble with the idea of tension in a pendulum. I've reasoned out my answers, but they're wrong. Am I missing a concept completely or am I overlooking a detail?

    1. The problem statement, all variables and given/known data

    The following questions deal with a pendulum in motion with angle not being its extreme end where v = 0 m/s

    1. T is smallest when angle= ± angle not


    2. The vertical component of tension is constant.


    3. T = Mg at some angle between zero and angle not.


    4. T is greater than Mg when angle=angle not


    5. T is largest at the bottom (angle=0)


    6. T equals Mg when angle = angle not




    2. Relevant equations

    sum of vertical forces = 0
    T cos A = mg
    sum of horizontal forces = 0
    T sin A = F

    3. The attempt at a solution

    1. T is smallest when angle= ± angle not
    True No motion occurs at this point so no centripital acceleration occurs

    2. The vertical component of tension is constant.
    True vertical component of T is always constant, it is equal to mg horizontal force always vary according to the angle

    3. T = Mg at some angle between zero and angle not.
    True at different points the system has the properties of T<mg and T>mg. You can obtain this change without passing through T=mg.

    4. T is greater than Mg when angle=angle not
    False T will be less than the weight at the top of the swing, because there's no motion and hence no centripetal acceleration

    5. T is largest at the bottom (angle=0)
    True The tension in a pendulum string will be greater than weight at the bottom of the swing, because it has to provide an upward net acceleration

    6. T equals Mg when angle = angle not
    False T < mg at the apex of the pendulums motion
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
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