Take the anti derivative of (X^2)/sqrt(1-x)soln' . let u=1-x

1. Jan 11, 2006

johnnyboy2005

take the anti derivative of (X^2)/sqrt(1-x)

soln'.... let u=1-x... then -du=dx and x^2 = (1-u)^2 (sub back in)...

this gives me -2*u^(1/2)*(15-10*u+3*u^2) /15.... (sorry for lack of proper terms)

anyway, this turns out to be wrong...where did i go wrong here?

2. Jan 11, 2006

benorin

Try this:

$$\int \frac{x^2}{\sqrt{1-x}}dx = -\int \frac{(1-u)^2}{\sqrt{u}}du = -\int u^{-\frac{1}{2}}(1-2u+u^2) du$$

then distribute the $u^{-\frac{1}{2}}$ term over the quadratic and integrate

3. Jan 11, 2006

johnnyboy2005

yeah...that's what i was getting but it was in a different form. Thanks a lot !!1