- #1
Harmony
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Show that for all values of t, the point P with the equation
x=2t^2, y=t^3 lies on the curve 8y^2=x^3
Find the equation of the tangent to the curve at point P.
The tangent meets the curve once again at point Q. Find the coordinates of point Q.
I can find the equation of the tangent.
After finding the tangent, I try to solve it by using the two equation. At the end I get 9t^2x^2-12t^4x+4t^6=2x^3. Is it the right way? It seems complicated.
x=2t^2, y=t^3 lies on the curve 8y^2=x^3
Find the equation of the tangent to the curve at point P.
The tangent meets the curve once again at point Q. Find the coordinates of point Q.
I can find the equation of the tangent.
After finding the tangent, I try to solve it by using the two equation. At the end I get 9t^2x^2-12t^4x+4t^6=2x^3. Is it the right way? It seems complicated.
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