Refer to diagram:Sorry guys. I posted an empty thread by mistake due to power failure. Here is the question.
Point A moves uniformly with velocity v so that the vector v is continually "aimed" at point B which in its turn moves rectilinearly and uniformly ith velocity u <v. At the initial moment of time v is perpendicular to u and the points are separatd by distance k. How soon will the points meet?
The Attempt at a Solution
Sorry guys. I posted an empty thread by mistake due to power failure
You don't need "kinematics", or even acceleration, just a clear head (and enough light to see the problem!).Well, I havent studied kinematics in very much details, not even circular motion. But I am able to solve simple questions on circular motion. I know simple usage of basic calculus. Please guide me to solve this, as its been a long time since i hav been trying this question.
Yes, I know where point B is after time "t". It will travel "ut" in positive direction of x axis.ah … and I thought your dog ate it!
You don't need "kinematics", or even acceleration, just a clear head (and enough light to see the problem!).
You simply need to know what θ is (or tanθ) …
and you can work that out because you know exactly where B is at time t, and you just subtract (x,y) from that.
Hi tim~Hi ritwik06!
(x,y) is the position of A … x along the x-axis, and y up the y-axis.
As you say, B is at position (k,ut).
So the vector AB is (k - x, ut - y), and so tanθ = (ut - y)/(k - x).
Well, I have shown all that I could. I have been trying to solve this for a long time. I have tried my best. I had even put it in introductory physics. The people who tried to help me did not have their concepts clear. I can even show you a PM from one of the members getting himself stuck at last and rgretting. Its now upto u whether u ish to help or not, of course if u know it urself.you have not done an attempt to solution.
Read it several times.Read this: