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Tangent line to curve Q

  • Thread starter ElDavidas
  • Start date
  • #1
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Can anybody help me out with this Q?

"A curve R in space has vector equation:

[tex] x = (sin(\pi u), u^2 - 1, u^2 + 3u + 3) [/tex]

u is a real number. Find a vector equation of the tangent line to R at the point (0, 0, 1)"
 

Answers and Replies

  • #2
siddharth
Homework Helper
Gold Member
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What are your ideas or thoughts on how to solve this problem? You need to show some work to get help.
 
  • #3
80
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Well, I originally thought of taking the gradient of x and then plugging in the values of (0,0,1). Not sure if this is the right way to go about it though.
 
  • #4
0rthodontist
Science Advisor
1,230
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The derivative of a curve at a point is indeed parallel to the tangent line (if the curve has nonzero speed at the point and a tangent line). But you can't just plug in (0, 0, 1) because you only have 1 variable-u. How do you find u such that x(u) = (0, 0, 1)?
 

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