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## Homework Statement

This is a very basic problem, though it did confuse me a little:

Find the tangent equations to the curve [tex]x=3t^2+1 \ , \ y = 2t^3+2[/tex] which intercepts the point (4,3).

## Homework Equations

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## The Attempt at a Solution

I took [tex]\frac{dy}{dx} = t = \frac{y-y_0}{x-x_0} = \frac{y-3}{x-4} \rightarrow y=t(x-4)+3[/tex]

What to do next? I don't think the equation works for all t.