- #1

Dustinsfl

- 2,285

- 5

y' = b*e[tex]^{bx}[/tex] = 10x

How can I solve for b here?

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- Thread starter Dustinsfl
- Start date

- #1

Dustinsfl

- 2,285

- 5

y' = b*e[tex]^{bx}[/tex] = 10x

How can I solve for b here?

- #2

- 3,475

- 257

y' = b*e[tex]^{bx}[/tex] = 10x

How can I solve for b here?

Your equation isn't right.

What condition(s) must be satisfied if [itex]y = 10x[/itex] is tangent to [itex]y = e^{bx}[/itex] at some point?

- #3

Dustinsfl

- 2,285

- 5

It has to be the derivative.

- #4

- 3,475

- 257

It has to be the derivative.

What has to be what derivative? Try to be precise when you are expressing ideas in mathematics.

Say I have two differentiable functions, [itex]f(x)[/itex] and [itex]g(x)[/itex]. What must be true if [itex]g[/itex] is tangent to [itex]f[/itex] at some point [itex]x_0[/itex]?

- #5

Dustinsfl

- 2,285

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- #6

- 3,475

- 257

As I already said, your equation is wrong, so there is no point trying to solve it for b.

Can you explain why you set the derivative of the exponential equal to 10x?

- #7

Dustinsfl

- 2,285

- 5

That is what I need the derivative to be equal.

- #8

- 3,475

- 257

That is what I need the derivative to be equal.

No it's not.

What properties of a curve and a line must be equal if the line is to be tangent to the curve at a point?

- #9

Dustinsfl

- 2,285

- 5

We can keep going around and circles all day but it isn't going to get anywhere.

- #10

- 3,475

- 257

We can keep going around and circles all day but it isn't going to get anywhere.

OK, good luck.

- #11

justsof

- 28

- 0

We can keep going around and circles all day but it isn't going to get anywhere.

"We" ? You are the one thinking in circles, jbunniii is actually trying to point you the way out of your circles, but it seems you just don't want to listen...

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