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Tangent Lines

  1. Feb 28, 2010 #1
    1. The problem statement, all variables and given/known data
    show that the tangent line to y=(x2+x-2)3+3 at (1,3) is also tangent to the curve at another point


    2. Relevant equations



    3. The attempt at a solution
    dy/dx=3(x2+x-2)2(2x+1)
    at 1
    dy/dx = 0
    y=mx+b
    b=3
    y=3
     
  2. jcsd
  3. Feb 28, 2010 #2

    rock.freak667

    User Avatar
    Homework Helper

    Then solving the equations y=3 and y=y=(x2+x-2)3+3 will give you two solutions, you know (1,3) is a solution, you just need to get the other solution.
     
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