- #1
teken894
- 25
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Here's a question from my Calc HW andI believe my approach is flawed...
Two functions
f(x) = x^2
g(x) = -x^2 + 6x -5
Find the two lines tangent to both functions
I thought I could find the slope where f' and g' are equal so I did:
f'(x) = 2x
g'(x) = -2x + 6
2x = -2x +6
x = 1.5
slope = 2(1.5) = 3
BUT that slope doesn't work as this simply finds an x on the two graphs where the two graphs have the same slope.
Help me please!
THE given answers are
y=2x-1
y=4x-4
Two functions
f(x) = x^2
g(x) = -x^2 + 6x -5
Find the two lines tangent to both functions
I thought I could find the slope where f' and g' are equal so I did:
f'(x) = 2x
g'(x) = -2x + 6
2x = -2x +6
x = 1.5
slope = 2(1.5) = 3
BUT that slope doesn't work as this simply finds an x on the two graphs where the two graphs have the same slope.
Help me please!
THE given answers are
y=2x-1
y=4x-4