Hi guys, i'm having a little trouble finding the equation of the tangent to the curve 2e^(xy) - ysinx = log(y) + 2 at the point (0,1).(adsbygoogle = window.adsbygoogle || []).push({});

I've basically concluded that either the equation should be used or either find the gradient at (0,1) through differentiation and then use (y-y1)=m(x-x1).

But i can't seem to get the derivative in terms of y. Any help or advice would be much appreciated, thank you.

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Tangent To The Curve

**Physics Forums | Science Articles, Homework Help, Discussion**