(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

f (x) = e^(3x) + sin(2x) + 3x +1

(a) Find a vector V that is tangent to the graph of y = f(x) at the point ( 0, 2).

(b) Find a vector N that is perpendicular to the graph of y = f(x) at the point ( 0, 2).

2. The attempt at a solution

The first step I took is to find the derivative of the function, since the problem is asking for a tangent at a point.

I got this: f'(x) = 3e^(3x) + 2cos(2x) + 3

However, I am unsure how to continue. The graph of "y = f(x)" is kind of confusing. I am thinking of maybe somehow getting parametric equations for the tangent line, which would allow me to build a vector. But I am unsure how to do this.

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# Homework Help: Tangent Vectors on a 2D Graph

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